MicroPython Forum (Archive)

Posted: **Tue Nov 24, 2015 8:28 pm**

Hi,
i try to register a user defined function for a periodic timer interupt on the wipy.
This works:

tim = Timer(1, mode=Timer.PERIODIC)
tim_a = tim.channel(Timer.A, freq=700)
tim_a.irq(handler=lambda t: pin_step.toggle())

This not. There is no error, the wipy just seems to ignore the handler silently.:

Code: Select all

def stepnext():
    pin_step.toggle()

tim = Timer(1, mode=Timer.PERIODIC)
tim_a = tim.channel(Timer.A, freq=700)
tim_a.irq(handler=lambda t: stepnext())
#I also tried this:
#tim_a.irq(handler=stepnext())

Am i missing something?
Thanks Thilo

Posted: **Tue Nov 24, 2015 10:11 pm**

According to some example found in the documentaton, this work like that :

Code: Select all

def stepnext(timer):
    pin_step.toggle()

tim = Timer(1, mode=Timer.PERIODIC)
tim_a = tim.channel(Timer.A, freq=700)
tim_a.irq(handler=stepnext)

Posted: **Tue Nov 24, 2015 10:43 pm**

Yep, thats it. I seems to have overlooked the parameter of the function.
Thanks a lot!

Posted: **Wed Nov 25, 2015 7:38 am**

This is surely a bug. Even with

Code: Select all

import micropython
micropython.alloc_emergency_exception_buf(100)

the version where the ISR has no argument quietly fails to run with no error message being reported.

MicroPython Forum (Archive)

registered function on Timerchannel gets not executed

registered function on Timerchannel gets not executed

Re: registered function on Timerchannel gets not executed

Re: registered function on Timerchannel gets not executed

Re: registered function on Timerchannel gets not executed