MicroPython Forum (Archive)

davef wrote: ↑

Fri Dec 25, 2020 4:39 am

Hi glenn20,

Thank you for the feedback. Anytime you see the word "seemed" it means that things did not seem to work 100% of the time. When looking at traceback messages sometimes it "seemed" that a programming error later in the program would throw up an error at a earlier line number.
I got into a habit of commenting-out every line and introducing them one at a time, until an error would pop-up.

For the ESP8266:
Today, I do not have to put a value in init() in rx8266.py so remove that issue.

Code: Select all

for msg in e:

of course throws a 'ESPNow' object is not iterable as you can only use this on the ESP32

I do not know other ways of getting the "callee-owned" tuple of bytearrays into a form that I can use. Off to check with Mr. Google.

Dave

pkt = e.irecv()
print("Peer MAC Address: {}".format(pkt[0]))   # MAC address
print("Message: {}".format(pkt[1]))   # Received message

peer, msg = e.irecv()
print("Peer MAC Adress: {}".format(peer))   # MAC address
print("Message: {}".format(msg))   # Received message

ESPNow.irecv([timeout])

As for `recv()<ESPNow.recv()>` except that ``irecv()`` will return a
"callee-owned" tuple of bytearrays.
That is, memory will be allocated once for the tuple and byte strings on
invocation of espnow.ESPNow() and re-used for subsequent calls to
`irecv()<ESPNow.irecv()>`. You must make copies if you
wish to keep the values across calls to ``irecv()``.

while True:
	msg = e.irecv()
	if msg:
		command = msg[1].decode('utf-8')
		print(command)

while True:
    msg = e.irecv()
    if msg:
        command = msg[1].decode('utf-8')
        print(command)
		
    del msg

..and a precompiled image for the ESP32 at https://drive.google.com/file/d/1IIStoi ... UgOrHRe7VF

davef wrote: ↑

Fri Dec 25, 2020 10:25 am

Found a snippet of code on how to grab the message content which works for my simple case.

...

I found that recv() didn't work for the ESP8266.

.. method:: ESPNow.recv([timeout]) (ESP32 only)

Something in espnow.rst that I do not understand:

import network

w0 = network.WLAN(network.STA_IF)
w0.active(True)

.. method:: ESPNow.send(mac, msg, [sync=True]) (ESP32 only)
ESPNow.send(msg) (ESP32 only)

davef wrote: ↑

Sat Dec 26, 2020 7:21 am

...
Taking the code above for ESP8266 receive, I have this block to process the commands:

Code: Select all

while True:
	msg = e.irecv()
	if msg:
		command = msg[1].decode('utf-8')
		print(command)

If I don't bail-out of the while block, then every 5-10 minutes I get another print(command).

I understand that tuples are immutable and I guess every time it goes around the loop
it has the same data in the tuple so nothing changes,

but why the long delay?

If msg is immutable how can a new (different) msg be received?

This seems to sort it:

Code: Select all

while True:
    msg = e.irecv()
    if msg:
        command = msg[1].decode('utf-8')
        print(command)
		
    del msg

I would like to leave the remote ready for new commands.

del msg

On each call to irecv() new data is written into those bytearrays (peer mac address and the message).