MicroPython Forum (Archive)

I have been working with micropython for awhile. my project now is to run the main without user can see the source code when mounting the pyb over USB. so I decide to use littlefs2 using this code:

Code: Select all

import os, pyb
os.umount('/flash')
p1 = pyb.Flash(start=0, len=32*1024)
p2 = pyb.Flash(start=32*1024)
os.VfsFat.mkfs(p1)
os.VfsLfs2.mkfs(p2)
os.mount(p1, '/flash')
os.mount(p2, '/data')
os.chdir('/flash')

and I mount the VfsLfs:

[/code]
import os, pyb
p2 = pyb.Flash(start=32*1024)
os.mount(p2, '/data')
[/code]

then I transfer to the partition of littlefs the main.py and boot.py files. But did't boot from it!:(

Im using pyb v1.1 with firmware MicroPython v1.14.

Is there any error in my steps or my understanding of littlefs was wrong?
any help?

Why should micropython boot from the littlefs volume? It looks at the partition, sees that it's FAT, mounts that and is happy.

smurf wrote: ↑

Wed Jun 02, 2021 1:42 pm

Why should micropython boot from the littlefs volume? It looks at the partition, sees that it's FAT, mounts that and is happy.

I dont want the end user to see or copy my code in the pyb , thats why I need to boot from the littlefs volume.

The end user can always get access to you r files, if it is on a valid partition. Not to mention flash dumps. using frozen bytecode is a little bit more effective as protection means.

thanks for you replay Roberthh , I understand your idea. but is there a way to boot and run the main from littlefs in hybrid filesystem?