I'm a little stuck here and maybe someone can help.

There are four bytearrays which have to be combined (for lack of a better word) into a fifth one using the fastest way possible.

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```
a = bytearray(240)
b = bytearray(240)
c = bytearray(240)
d = bytearray(240)
result = bytearray(240)
a = [<arbitrary byte>, 0, 0, 0, <arbitrary byte>, 0, 0, 0, ... and so on ..., <arbitrary byte>, 0, 0, 0]
b = [0, <arbitrary byte>, 0, 0, 0, <arbitrary byte>, 0, 0, ... and so on ..., 0, <arbitrary byte>, 0, 0]
c = [0, 0, <arbitrary byte>, 0, 0, 0, <arbitrary byte>, 0, ... and so on ..., 0, 0, <arbitrary byte>, 0]
d = [0, 0, 0, <arbitrary byte>, 0, 0, 0, <arbitrary byte>, ... and so on ..., 0, 0, 0, <arbitrary byte>]
```

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`result = [<byte 0 from a>, <byte 1 from b>, <byte 2 from c>, <byte 3 from d>, <byte 4 from a>, ... and so on ..., <byte 236 from a>, <byte 237 from b>, <byte 238 from c>, <byte 239 from d>]`

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```
for i in range(0,240):
result[i] = a[i] + b[i] + c[i] + d[i]
```

Something like

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`result = a | b | c | d`

Has someone perhaps a clever idea how to do this as fast as possible?

Thanks a lot in advance

Blechi